NCERT Solutions For Class 10 Science Chapter 11 The Human Eye and the Colourful World

Class 10 Science Chapter 11 The Human Eye and the Colourful World

1. Exercise Questions
2. Intext Questions

NCERT Solutions For Class 10 Science Chapter 11 The Human Eye And The Colourful World in this step-by-step answer guide. In some of State Boards and CBSE schools, students are taught thru NCERT books. As the chapter comes to an end, students are requested few questions in an exercising to evaluate their expertise of the chapter.

Students regularly want guidance managing those NCERT Solutions. It’s most effective natural to get stuck withinside the exercises while solving them so that you can assist students score higher marks, we’ve provided step by step NCERT answers for all exercises of Class ten Science The Human Eye And The Colourful World so you can be looking for assist from them.

Students should solve those exercises carefully as questions withinside the final exams are requested from those, so these exercises immediately have an impact on students’ final score. Find all NCERT Solutions for Class ten Science The Human Eye And The Colourful World below and prepare in your tests easily.

NCERT Solutions For Class 10 Science Chapter 11 The Human Eye and the Colourful World

Class 10 Science Chapter 11 The Human Eye and the Colourful World

EXERCISE QUESTIONS

 

Q.1 . The human eye can focus objects at different distances by adjusting the focal length of the eye lens . This is due to

( a ) presbyopia

( b ) accommodation

( c ) near – sightedness

( d ) far – sightedness

Ans . Correct option : ( b )

Explanation : Human eye can change the focal length of the eye lens to see the objects situated at various distances from the eye . This is possible due to the power of accommodation of the eye lens .

Q. 2. The human eye forms the image of an object at its

( a ) cornea

( b ) iris

( c ) pupil

( d ) retina

Ans . Correct option : ( d )

Explanation : The human eye forms the image of an object at its retina .

Q. 3. The least distance of distinct vision for a young adult with normal vision is about

( a ) 25 m

( b ) 2.5 cm

( c ) 25 cm

( d ) 2.5 m

Ans . Correct option : ( c )

Explanation : The least distance of distinct vision is the minimum distance of an object to see clear and distinct image . It is 25 cm for a young adult with normal visions .

Q. 4. The change in focal length of an eye lens is caused by the action of the

( a ) pupil

( b ) retina

( c ) ciliary muscles

( d ) iris

Ans . Correct option : ( c )

Explanation : The relaxation or contraction of ciliary muscles changes the curvature of the eye lens . The change in curvature of the eye lens changes the focal length of the eyes . Hence , the change in focal length of an eye lens is caused by the action of ciliary muscles .

Q. 5. A person needs a lens of power -5.5 dioptres for correcting his distant vision . For correcting his near vision he needs a lens of power +1.5 dioptre . What is the focal length of the lens required for correcting

( i ) distant vision , and

( ii ) near vision

Ans . Power of the lens for correcting distant vision , P₁ = -5.5 D

Power of the lens for correcting near vision , P₂ = +1.5 D

( i ) Focal length for correcting distant vision ,

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( ii ) Power of near vision is measured relative to the main part of the lens .

So , focal length of required lens ,

Focal length of the lens required for correcting , distant vision is -0.181 m and , near vision is 0.667 m .

Q. 6. The far point of a myopic person is 80 cm in front of the eye . What is the nature and power of the lens required to correct the problem ?

Ans . The person is suffering from an eye defect called myopia . In this defect , the image is formed in front of the retina . Hence , a concave lens is used to correct this defect of vision .

Object distance , u = infinity = ∞

Image distance , v = -80 cm

Focal length = f

According to the lens formula ,

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f = -80 cm = -0.8 m

We know that ,

Power ,

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A concave lens of power -1.25 D is required by the person to correct the defect .

Q. 7. Make a diagram to show how hypermetropia is corrected . The near point of a hypermetropic eye is 1 m . What is the power of the lens required to correct this defect ? Assume that the near point of the normal eye is 25 cm .

Ans . A person suffering from hypermetropia can see distinct objects clearly but faces difficulty in seeing nearby objects clearly . It happens because the eye lens focuses the incoming divergent rays beyond the retina . This defect of vision is corrected by using a convex lens .

A convex lens of suitable power converges the incoming light in such a way that the image is formed on the retina , as shown in the following figure .

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The convex lens actually creates a virtual image of a nearby object at the near point of vision ( N ) of the person suffering from hypermetropia .

The given person will be able to clearly see the object kept at 25 cm ( near point of the normal eye ) , if the image of the object is formed at his near point , which is given as 1 m .

Given that ,

Object distance , u = -25 cm

Image distance , v = -1 m = -100 cm

For focal length , f

Using the lens formula ,

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A convex lens of power +3.0 D is required to correct the defect .

Q. 8. Why is a normal eye not able to see clearly the objects placed closer than 25 cm ?

Ans . This is because the ciliary muscles of eyes are unable to contract beyond a certain limit .

If the object is placed at a distance less than 25 cm from the eye , then the object appears blurred because light rays coming from the object meet beyond the retina .

Q.9 . What happens to the image distance in the eye when we increase the distance of an object from the eye ?

Ans . Since the size of eyes cannot increase or decrease , the image distance remains constant .

When we increase the distance of an object from the eye , the image distance in the eye does not change .

The increase in the object distance is compensated by the change in the focal length of the eye lens . The focal length of the eyes changes in such a way that the image is always formed at the retina of the eye .

Q. 10.Why do stars twinkle ?

Ans . Stars emit their own light and they twinkle due to the atmospheric refraction of light . Stars are very far away from the earth . Hence , they are considered as point sources of light . When the light coming from stars enters the earth’s atmosphere , it gets refracted at different levels because of the variation in the air density at different levels of the atmosphere .

When the star light refracted by the atmosphere comes more towards us , it appears brighter than when it comes less towards us . Therefore , it appears as if the stars are twinkling at night .

Q.11. Explain why the planets do not twinkle .

Ans . Planets do not emit light . However , they become visible due to reflection of light falling on them . They do not twinkle because they appear larger in size than the stars as they are relatively closer to earth .

Planets can be considered as a collection of a large number of point – size sources of light . The different parts of these planets produce either brighter or dimmer effect in such a way that the average of brighter and dimmer effect is zero . Hence , the twinkling effects of the planets are nullified and they do not twinkle .

Q.12.Why does the Sun appear reddish early in the morning ?

Ans . During sunrise , the light rays coming from the Sun have to travel a greater distance in the earth’s atmosphere before reaching our eyes . In this journey , the shorter wavelengths of lights are scattered out and only longer wavelengths are able to reach our eyes .

Since blue colour has a shorter wavelength and red colour has a longer wavelength , the red colour is able to reach our eyes after the atmospheric scattering of light . Therefore , the Sun appears reddish early in the morning .

Q. 13.Why does the sky appear dark instead of blue to an astronaut ?

Ans . The sky appears dark instead of blue to an astronaut because there is no atmosphere in the outer space that can scatter the sunlight .

As the sunlight is not scattered , no scattered light reaches the eyes of the astronauts and the sky appears black to them .

INTEXT QUESTIONS

Page 190

Q. 1. What is meant by power of accommodation of the eye ? [ NCERT Q. 1 , Page 190 ]

Ans . When the ciliary muscles are relaxed , the eye lens becomes thin , the focal length increases and the distant objects are clearly visible to the eyes . To see the nearby objects clearly , the ciliary muscles contract making the eye lens thicker .

Thus , the focal length of the eye lens decreases and the nearby objects become visible to the eyes . Hence , the human eye lens is able to adjust its focal length to view both distant and nearby objects on the retina .

This ability is called the power of accommodation of the eyes .

Q. 2. A person with a myopic eye cannot see objects beyond 1.2 m distinctly . What should be the type of the corrective lens used to restore proper vision ? [ NCERT Q. 2 , Page 190 ]

Ans . The person is able to see nearby objects clearly , but the person is unable to see objects beyond 1.2 m . This happens because the image of an object beyond 1.2 m is formed in front of the retina and not at the retina , as shown in the given figure .

To correct this defect of vision , he must use a concave lens . The concave lens will bring the image back to the retina as shown in the given figure .

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Q. 3. What is the far point and near point of the human eye with normal vision ? [ NCERT Q. 3 , Page 190 ]

Ans . The near point of the eye is the minimum distance of the object from the eye , which can be seen distinctly without strain . For a normal human eye , this distance is 25 cm .

The far point of the eye is the maximum distance to which the eye can see the objects clearly . The far point of the normal human eye is infinity .

Q. 4. A student has difficulty in reading the blackboard while sitting in the last row . What could be the defect the child is suffering from ? How can it be corrected ? [ NCERT Q. 4 , Page 190 ]

Ans . The student has difficulty in reading the blackboard while sitting in the last row . It shows that he is unable to see distant objects clearly .

He is suffering from myopia . This defect can be corrected by using a concave lens .

Benefits of NCERT Solutions

NCERT’s Class 10 solution contains extremely important points, and for each chapter, each concept has been simplified to make it easier to remember and increase your chances of achieving excellent exam results. Exam Preparation References Here are some tips on how these solutions can help you prepare for the exam.

  1. This helps students solve many of the problems in each chapter and encourages them to make their concepts more meaningful.
  2. NCERT Solutions for Class 10 solutions encourage you to update your knowledge and refine your concepts so that you can get good results in the exam.
  3. These solutions are the best exam materials, allowing you to learn more about your week and your strengths. To get good results in the exam, it is important to overcome your weaknesses.
  4. Most of the questions in the exam are formulated in a similar way to NCERT textbooks. Therefore, students should review the solutions in each chapter in order to better understand the topic.
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Tips & Strategies for Class 10 Exam Preparation

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  2. Please refer to the NCERT solution available on the cbsestudyguru website to clarify your concepts every time you prepare for the exam.
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  4. It is important to clear all your doubts before the exam with your teachers or Alex (an Al study Bot). 
  5. When you read or study a chapter, write down algorithm formulas, theorems, etc., and review them quickly before the exam.
  6. Practice an ample number of question papers to make your concepts stronger. 
  7. Take rest and a proper meal.  Don’t stress too much. 

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